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Date May 2013 Marks available 7 Reference code 13M.2.sl.TZ2.4
Level SL only Paper 2 Time zone TZ2
Command term Find Question number 4 Adapted from N/A

Question

Line L1 has equation r1=(1061)+s(252) and line L2 has equation r2=(213)+t(352) .

Lines L1 and L2 intersect at point A. Find the coordinates of A.

Markscheme

appropriate approach     (M1)

eg   (1061)+s(252)=(213)+t(352) , L1=L2

any two correct equations     A1A1

eg   10+2s=2+3t , 65s=1+5t , 12s=3+2t

attempt to solve     (M1)

eg substituting one equation into another

one correct parameter     A1

eg   s=1 , t=2

correct substitution     (A1)

eg   2+3(2) , 1+5(2) , 3+2(2)

A = (8, 11, 1) (accept column vector)     A1     N4

[7 marks]

Examiners report

Most students were able to set up one or more equations, but few chose to use their GDCs to solve the resulting system. Algebraic errors prevented many of these candidates from obtaining the final three marks. Some candidates stopped after finding the value of s and/or t.

Syllabus sections

Topic 4 - Vectors » 4.4 » Finding the point of intersection of two lines.
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