Date | May 2013 | Marks available | 7 | Reference code | 13M.2.sl.TZ2.4 |
Level | SL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 4 | Adapted from | N/A |
Question
Line L1 has equation r1=(106−1)+s(2−5−2) and line L2 has equation r2=(21−3)+t(352) .
Lines L1 and L2 intersect at point A. Find the coordinates of A.
Markscheme
appropriate approach (M1)
eg (106−1)+s(2−5−2)=(21−3)+t(352) , L1=L2
any two correct equations A1A1
eg 10+2s=2+3t , 6−5s=1+5t , −1−2s=−3+2t
attempt to solve (M1)
eg substituting one equation into another
one correct parameter A1
eg s=−1 , t=2
correct substitution (A1)
eg 2+3(2) , 1+5(2) , −3+2(2)
A = (8, 11, 1) (accept column vector) A1 N4
[7 marks]
Examiners report
Most students were able to set up one or more equations, but few chose to use their GDCs to solve the resulting system. Algebraic errors prevented many of these candidates from obtaining the final three marks. Some candidates stopped after finding the value of s and/or t.