Date | May 2018 | Marks available | 3 | Reference code | 18M.1.sl.TZ1.5 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
Let f(x)=1√2x−1f(x)=1√2x−1, for x>12x>12.
Find ∫(f(x))2dx∫(f(x))2dx.
Part of the graph of f is shown in the following diagram.
The shaded region R is enclosed by the graph of f, the x-axis, and the lines x = 1 and x = 9 . Find the volume of the solid formed when R is revolved 360° about the x-axis.
Markscheme
correct working (A1)
eg ∫12x−1dx,∫(2x−1)−1,12x−1,∫(1√u)2du2∫12x−1dx,∫(2x−1)−1,12x−1,∫(1√u)2du2
∫(f(x))2dx=12ln(2x−1)+c∫(f(x))2dx=12ln(2x−1)+c A2 N3
Note: Award A1 for 12ln(2x−1)12ln(2x−1).
[3 marks]
attempt to substitute either limits or the function into formula involving f 2 (accept absence of ππ / dx) (M1)
eg ∫91y2dx,π∫(1√2x−1)2dx,[12ln(2x−1)]91∫91y2dx,π∫(1√2x−1)2dx,[12ln(2x−1)]91
substituting limits into their integral and subtracting (in any order) (M1)
eg π2(ln(17)−ln(1)),π(0−12ln(2×9−1))π2(ln(17)−ln(1)),π(0−12ln(2×9−1))
correct working involving calculating a log value or using log law (A1)
eg ln(1)=0,ln(171)ln(1)=0,ln(171)
π2ln17(accept πln√17)π2ln17(accept πln√17) A1 N3
Note: Full FT may be awarded as normal, from their incorrect answer in part (a), however, do not award the final two A marks unless they involve logarithms.
[4 marks]