Date | May Example question | Marks available | 2 | Reference code | EXM.2.AHL.TZ0.18 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Write down | Question number | 18 | Adapted from | N/A |
Question
The adjacency matrix of the graph G, with vertices P, Q, R, S, T is given by:
Draw the graph of G.
Define an Eulerian circuit.
Write down an Eulerian circuit in G starting at P.
Define a Hamiltonian cycle.
Explain why it is not possible to have a Hamiltonian cycle in G.
Find the number of walks of length 5 from P to Q.
Which pairs of distinct vertices have more than 15 walks of length 3 between them?
Markscheme
A3
Note: Award A2 for one missing or misplaced edge,
A1 for two missing or misplaced edges.
[3 marks]
an Eulerian circuit is one that contains every edge of the graph exactly once A1
[1 mark]
a possible Eulerian circuit is
P → Q → S → P → Q → Q → R → T → R → R → P A2
[2 marks]
a Hamiltonian cycle passes through each vertex of the graph A1
exactly once A1
[2 marks]
to pass through T, you must have come from R and must return to R. R3
hence there is no Hamiltonian cycle
[3 marks]
using the adjacency matrix A = , (M1)
we need the entry in the first row second column of the matrix A5 (M1)
A5 = (A1)
hence there are 309 ways A1
[4 marks]
A3 = (M1)
hence the pairs of vertices are PQ, PR and QR A1A1A1
[4 marks]