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Date May 2022 Marks available 4 Reference code 22M.2.SL.TZ1.9
Level Standard Level Paper Paper 2 Time zone Time zone 1
Command term Find Question number 9 Adapted from N/A

Question

A bakery makes two types of muffins: chocolate muffins and banana muffins.

The weights, C grams, of the chocolate muffins are normally distributed with a mean of 62g and standard deviation of 2.9g.

The weights, B grams, of the banana muffins are normally distributed with a mean of 68g and standard deviation of 3.4g.

Each day 60% of the muffins made are chocolate.

On a particular day, a muffin is randomly selected from all those made at the bakery.

The machine that makes the chocolate muffins is adjusted so that the mean weight of the chocolate muffins remains the same but their standard deviation changes to σg. The machine that makes the banana muffins is not adjusted. The probability that the weight of a randomly selected muffin from these machines is less than 61g is now 0.157.

Find the probability that a randomly selected chocolate muffin weighs less than 61g.

[2]
a.

In a random selection of 12 chocolate muffins, find the probability that exactly 5 weigh less than 61g.

[2]
b.

Find the probability that the randomly selected muffin weighs less than 61g.

[4]
c.i.

Given that a randomly selected muffin weighs less than 61g, find the probability that it is chocolate.

[3]
c.ii.

Find the value of σ.

[5]
d.

Markscheme

PC<61         (M1)

=0.365112

=0.365         A1

 

[2 marks]

a.

recognition of binomial eg  X~B12,0.365         (M1)

PX=5=0.213666

=0.214         A1

 

[2 marks]

b.

Let CM represent ‘chocolate muffin’ and BM represent ‘banana muffin’

P(B<61)=0.0197555...         (A1)


EITHER

PCM×PC<61CM+PBM×PB<61BM  (or equivalent in words)         (M1)


OR

tree diagram showing two ways to have a muffin weigh <61         (M1)


THEN

0.6×0.365+0.4×0.0197         (A1)

=0.226969

=0.227         A1

 

[4 marks]

c.i.

recognizing conditional probability         (M1)

 

Note: Recognition must be shown in context either in words or symbols, not just PAB

 

0.6×0.3651120.226969         (A1)

=0.965183

=0.965         A1

 

[3 marks]

c.ii.

METHOD 1

PCM×PC<61CM×PBM×PB<61BM=0.157         (M1)

0.6×PC<61+0.4×0.0197555=0.157

PC<61=0.248496         (A1)

attempt to solve for σ using GDC         (M1)


Note:
Award (M1) for a graph or table of values to show their PC<61 with a variable standard deviation.


σ=1.47225

σ=1.47g         A2

 

METHOD 2

PCM×PC<61CM×PBM×PB<61BM=0.157         (M1)

0.6×PC<61+0.4×0.0197555=0.157

PC<61=0.248496         (A1)

use of inverse normal to find z score of their PC<61         (M1)

z=-0.679229

correct substitution         (A1)

61-62σ=-0.679229

σ=1.47225

σ=1.47g         A1

 

[5 marks]

d.

Examiners report

This question was common to both HL and SL papers.

The first two parts of this question were generally well done, with many candidates demonstrating an understanding of how to find, using their GDC, the required probability from a normal distribution in part (a), and recognising the binomial probability in part (b).

Parts (c) and (d) were not done well, although many that were able to make progress in part (d) were often able to give concise solutions. Most that attempted part (c) did very poorly, while few attempted part (d). Both parts proved challenging, principally due to difficulties in determining the different possible outcomes with combined events. In part (c)(i), tree diagrams were unfortunately rarely seen, as were attempts to set out the ways of selecting a muffin weighing less than 61 g, either in words, or using appropriate notation involving probabilities. Those who did understand these concepts on the other hand were much more likely to be able to find the conditional probability in part (c)(ii) and be successful in part (d). Common errors included not considering both types of muffin, and in part (d) using a probability instead of a z-value.

a.
[N/A]
b.
[N/A]
c.i.
[N/A]
c.ii.
[N/A]
d.

Syllabus sections

Topic 4—Statistics and probability » SL 4.6—Combined, mutually exclusive, conditional, independence, prob diagrams
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