Date | November 2009 | Marks available | 6 | Reference code | 09N.2.hl.TZ0.4 |
Level | HL only | Paper | 2 | Time zone | TZ0 |
Command term | Find and Hence | Question number | 4 | Adapted from | N/A |
Question
When (1+x2)2(1+x2)2 , n∈N , is expanded in ascending powers of x , the coefficient of x3 is 70.
(a) Find the value of n .
(b) Hence, find the coefficient of x2 .
Markscheme
(a) coefficient of x3 is (n3)(12)3=70 M1(A1)
n!3!(n−3)!×18=70 (A1)
⇒n(n−1)(n−2)48=70 (M1)
n=16 A1
(b) (162)(12)2=30 A1
[6 marks]
Examiners report
Most candidates were able to answer this question well.