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Date November 2010 Marks available 4 Reference code 10N.1.hl.TZ0.3
Level HL only Paper 1 Time zone TZ0
Command term Expand and Simplify Question number 3 Adapted from N/A

Question

Expand and simplify (x22x)4.

Markscheme

(x22x)4=(x2)4+4(x2)3(2x)+6(x2)2(2x)2+4(x2)(2x)3+(2x)4     (M1)

=x88x5+24x232x+16x4     A3

Note: Deduct one A mark for each incorrect or omitted term.

 

[4 marks]

Examiners report

Most candidates solved this question correctly with most candidates who explained how they obtained their coefficients using Pascal’s triangle rather than the combination formula.

Syllabus sections

Topic 1 - Core: Algebra » 1.3 » The binomial theorem: expansion of (a+b)n, nN .
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