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Date May 2008 Marks available 7 Reference code 08M.1.hl.TZ1.9
Level HL only Paper 1 Time zone TZ1
Command term Find Question number 9 Adapted from N/A

Question

The random variable T has the probability density function

f(t)=π4cos(πt2), 1t1.

Find

(a)     P(T = 0) ;

(b)     the interquartile range.

Markscheme

(a)     Any consideration of 00f(x)dx     (M1)

0     A1     N2

 

(b)     METHOD 1

Let the upper and lower quartiles be a and −a

π41acosπt2dt=0.25     M1

[π4×2πsinπt2]1a=0.25     A1

[12sinπt2]1a=0.25

[1212sinπa2]=0.25     A1

12sinπa2=14

sinπa2=12

πa2=π6

a=13     A1

Since the function is symmetrical about t = 0 ,

interquartile range is 13(13)=23     R1

METHOD 2

π4aacosπt2dt=0.5=π2a0cosπt2dt     M1A1

[sinaπ2]=0.5     A1

aπ2=π6

a=13     A1

The interquartile range is 23     R1

[7 marks]

Examiners report

All but the best candidates struggled with part (a). The vast majority either did not attempt it or let t = 1 . There was no indication from any of the scripts that candidates wasted an undue amount of time in trying to solve part (a). Many candidates attempted part (b), but few had a full understanding of the situation and hence were unable to give wholly correct answers.

Syllabus sections

Topic 5 - Core: Statistics and probability » 5.5 » Concept of discrete and continuous random variables and their probability distributions.

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