Date | May 2012 | Marks available | 6 | Reference code | 12M.1.hl.TZ2.8 |
Level | HL only | Paper | 1 | Time zone | TZ2 |
Command term | Show that | Question number | 8 | Adapted from | N/A |
Question
Let x3y=asinnx . Using implicit differentiation, show that
x3d2ydx2+6x2dydx+(n2x2+6)xy=0 .
Markscheme
x3y=asinnx
attempt to differentiate implicitly M1
⇒3x2y+x3dydx=ancosnx A2
Note: Award A1 for two out of three correct, A0 otherwise.
⇒6xy+3x2dydx+3x2dydx+x3d2ydx2=−an2sinnx A2
Note: Award A1 for three or four out of five correct, A0 otherwise.
⇒6xy+6x2dydx+x3d2ydx2=−an2sinnx
⇒x3d2ydx2+6x2dydx+6xy+n2x3y=0 A1
⇒x3d2ydx2+6x2dydx+(n2x2+6)xy=0 AG
[6 marks]
Examiners report
Candidates who are comfortable using implicit differentiation found this to be a fairly straightforward question and were able to answer it in just a few lines. Many candidates, however, were unable to differentiate x3y with respect to x and were therefore unable to proceed. Candidates whose first step was to write y=asinnxx3 were given no credit since the question required the use of implicit differentiation.