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Date May 2012 Marks available 6 Reference code 12M.1.hl.TZ2.8
Level HL only Paper 1 Time zone TZ2
Command term Show that Question number 8 Adapted from N/A

Question

Let x3y=asinnx . Using implicit differentiation, show that

x3d2ydx2+6x2dydx+(n2x2+6)xy=0 .

Markscheme

x3y=asinnx

attempt to differentiate implicitly     M1

3x2y+x3dydx=ancosnx     A2 

Note: Award A1 for two out of three correct, A0 otherwise.

 

6xy+3x2dydx+3x2dydx+x3d2ydx2=an2sinnx     A2 

Note: Award A1 for three or four out of five correct, A0 otherwise.

 

6xy+6x2dydx+x3d2ydx2=an2sinnx

x3d2ydx2+6x2dydx+6xy+n2x3y=0     A1

x3d2ydx2+6x2dydx+(n2x2+6)xy=0     AG

[6 marks]

Examiners report

Candidates who are comfortable using implicit differentiation found this to be a fairly straightforward question and were able to answer it in just a few lines. Many candidates, however, were unable to differentiate x3y with respect to x and were therefore unable to proceed. Candidates whose first step was to write y=asinnxx3 were given no credit since the question required the use of implicit differentiation.

Syllabus sections

Topic 6 - Core: Calculus » 6.2 » Implicit differentiation.

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