Date | November 2015 | Marks available | 4 | Reference code | 15N.1.hl.TZ0.7 |
Level | HL only | Paper | 1 | Time zone | TZ0 |
Command term | Show that | Question number | 7 | Adapted from | N/A |
Question
A curve is defined by xy=y2+4xy=y2+4.
Show that there is no point where the tangent to the curve is horizontal.
Find the coordinates of the points where the tangent to the curve is vertical.
Markscheme
xdydx+y=2ydydxxdydx+y=2ydydx M1A1
a horizontal tangent occurs if dydx=0dydx=0 so y=0y=0 M1
we can see from the equation of the curve that this solution is not possible (0=4)(0=4) and so there is not a horizontal tangent R1
[4 marks]
dydx=y2y−xdydx=y2y−x or equivalent with dxdydxdy
the tangent is vertical when 2y=x2y=x M1
substitute into the equation to give 2y2=y2+42y2=y2+4 M1
y=±2y=±2 A1
coordinates are (4, 2), (−4, −2)(4, 2), (−4, −2) A1
[4 marks]
Total [8 marks]