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Date November 2015 Marks available 4 Reference code 15N.1.hl.TZ0.7
Level HL only Paper 1 Time zone TZ0
Command term Show that Question number 7 Adapted from N/A

Question

A curve is defined by xy=y2+4xy=y2+4.

Show that there is no point where the tangent to the curve is horizontal.

[4]
a.

Find the coordinates of the points where the tangent to the curve is vertical.

[4]
b.

Markscheme

xdydx+y=2ydydxxdydx+y=2ydydx     M1A1

a horizontal tangent occurs if dydx=0dydx=0 so y=0y=0     M1

we can see from the equation of the curve that this solution is not possible (0=4)(0=4) and so there is not a horizontal tangent     R1

[4 marks]

a.

dydx=y2yxdydx=y2yx or equivalent with dxdydxdy

the tangent is vertical when 2y=x2y=x     M1

substitute into the equation to give 2y2=y2+42y2=y2+4     M1

y=±2y=±2     A1

coordinates are (4, 2), (4, 2)(4, 2), (4, 2)     A1

[4 marks]

Total [8 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 6 - Core: Calculus » 6.1 » The derivative interpreted as a gradient function and as a rate of change.

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