Date | May 2014 | Marks available | 5 | Reference code | 14M.2.hl.TZ1.5 |
Level | HL only | Paper | 2 | Time zone | TZ1 |
Command term | Find and Write down | Question number | 5 | Adapted from | N/A |
Question
The shaded region S is enclosed between the curve y=x+2cosx, for 0⩽, and the line y = x, as shown in the diagram below.
Find the coordinates of the points where the line meets the curve.
The region S is rotated by 2\pi about the x-axis to generate a solid.
(i) Write down an integral that represents the volume V of the solid.
(ii) Find the volume V.
Markscheme
(a) \frac{\pi }{2}(1.57),{\text{ }}\frac{{3\pi }}{2}(4.71) A1A1
hence the coordinates are \left( {\frac{\pi }{2},{\text{ }}\frac{\pi }{2}} \right),{\text{ }}\left( {\frac{{3\pi }}{2},{\text{ }}\frac{{3\pi }}{2}} \right) A1
[3 marks]
(i) \pi \int_{\frac{\pi }{2}}^{\frac{{3\pi }}{2}} {\left( {{x^2} - {{(x + 2\cos x)}^2}} \right){\text{d}}x} A1A1A1
Note: Award A1 for {x^2} - {(x + 2\cos x)^2}, A1 for correct limits and A1 for \pi .
(ii) 6{\pi ^2}{\text{ }}( = 59.2) A2
Notes: Do not award ft from (b)(i).
[5 marks]