Date | May 2017 | Marks available | 3 | Reference code | 17M.2.hl.TZ2.3 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Calculate | Question number | 3 | Adapted from | N/A |
Question
Packets of biscuits are produced by a machine. The weights XX, in grams, of packets of biscuits can be modelled by a normal distribution where X∼N(μ, σ2)X∼N(μ, σ2). A packet of biscuits is considered to be underweight if it weighs less than 250 grams.
The manufacturer makes the decision that the probability that a packet is underweight should be 0.002. To do this μμ is increased and σσ remains unchanged.
The manufacturer is happy with the decision that the probability that a packet is underweight should be 0.002, but is unhappy with the way in which this was achieved. The machine is now adjusted to reduce σσ and return μμ to 253.
Given that μ=253μ=253 and σ=1.5σ=1.5 find the probability that a randomly chosen packet of biscuits is underweight.
Calculate the new value of μμ giving your answer correct to two decimal places.
Calculate the new value of σσ.
Markscheme
P(X<250)=0.0228P(X<250)=0.0228 (M1)A1
[2 marks]
250−μ1.5=−2.878…250−μ1.5=−2.878… (M1)(A1)
⇒μ=254.32⇒μ=254.32 A1
Notes: Only award A1 here if the correct 2dp answer is seen. Award M0 for use of 1.521.52.
[3 marks]
250−253σ=−2.878…250−253σ=−2.878… (A1)
⇒σ=1.04⇒σ=1.04 A1
[2 marks]