Find the solution of ${\log _2}x - {\log _2}5 = 2 + {\log _2}3$.

${\log _2}x - {\log _2}5 = 2 + {\log _2}3$

collecting at least two log terms     (M1)

eg$\,\,\,\,\,$${\log _2}\frac{x}{5} = 2 + {\log _2}3{\text{ or }}{\log _2}\frac{x}{{15}} = 2$

obtaining a correct equation without logs     (M1)

eg$\,\,\,\,\,$$\frac{x}{5} = 12$$\,\,\,$OR$\,\,\,$$\frac{x}{{15}} = {2^2}$     (A1)

$x = 60$     A1

[4 marks]