| Date | May 2013 | Marks available | 3 | Reference code | 13M.3.HL.TZ2.17 |
| Level | Higher level | Paper | Paper 3 | Time zone | Time zone 2 |
| Command term | Calculate | Question number | 17 | Adapted from | N/A |
Question
This question is about relativistic mechanics.
A proton, after acceleration from rest through a potential difference V, has momentum 1600MeVc–1.
Calculate the value of V.
Markscheme
E=√p2c2+(mc2)2=√16002+9382≈1855(MeV);
ΔE=1855-938=917(MeV);
potential difference, V≈920(MV); (this marking point must be explicit)
Award [3] for a bald correct answer.
Examiners report
In any question with units expressed in terms of c there is potential for confusion. However many candidates are now able use the relativistic energy - momentum equation correctly. (a) was well answered by many.
Syllabus sections
Option A: Relativity » Option A: Relativity (Additional higher level option topics) » A.4 – Relativistic mechanics (HL only)
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