| Date | May 2013 | Marks available | 3 | Reference code | 13M.3.HL.TZ1.15 |
| Level | Higher level | Paper | Paper 3 | Time zone | Time zone 1 |
| Command term | Calculate | Question number | 15 | Adapted from | N/A |
Question
This question is about relativistic dynamics.
A proton is accelerated from rest by a potential difference V and reaches a speed of 2.5×108 m s–1. Calculate V.
Markscheme
ym0c2=m0c2+eV;
γ=1.81;
7.7×108(V) ;
Examiners report
This was poorly done although there were some very good answers. A significant minority of candidates used the non-relativistic equation for kinetic energy
Syllabus sections
Option A: Relativity » Option A: Relativity (Additional higher level option topics) » A.4 – Relativistic mechanics (HL only)
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