| Date | May 2017 | Marks available | 2 | Reference code | 17M.2.HL.TZ1.4 |
| Level | Higher level | Paper | Paper 2 | Time zone | Time zone 1 |
| Command term | Calculate | Question number | 4 | Adapted from | N/A |
Question
A heater in an electric shower has a power of 8.5 kW when connected to a 240 V electrical supply. It is connected to the electrical supply by a copper cable.
The following data are available:
Length of cable = 10 m
Cross-sectional area of cable = 6.0 mm2
Resistivity of copper = 1.7 × 10–8 Ω m
Calculate the power dissipated in the cable.
Markscheme
power = «352 × 0.028» = 34 «W»
Allow 35 – 36 W if unrounded figures for R or I are used.
Allow ECF from (a)(i) and (a)(ii).
Examiners report
[N/A]
Syllabus sections
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