Date | November 2015 | Marks available | 3 | Reference code | 15N.2.sl.TZ0.5 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 5 | Adapted from | N/A |
Question
Let C and D be independent events, with P(C)=2k and P(D)=3k2, where 0<k<0.5.
Write down an expression for P(C∩D) in terms of k.
Given that P(C∩D)=0.162 find k.
Find P(C′|D).
Markscheme
P(C∩D)=2k×3k2 (A1)
P(C∩D)=6k3 A1 N2
[2 marks]
their correct equation (A1)
eg2k×3k2=0.162, 6k3=0.162
k=0.3 A1 N2
METHOD 1
finding their P(C′∩D) (seen anywhere) (A1)
eg 0.4×0.27,0.27−0.162,0.108
correct substitution into conditional probability formula (A1)
egP(C′|D)=P(C′∩D)0.27, (1−2k)(3k2)3k2
P(C′|D)=0.4 A1 N2
METHOD 2
recognizing P(C′|D)=P(C′) A1
finding their P(C′)=1−P(C) (only if first line seen) (A1)
eg1−2k, 1−0.6
P(C′|D)=0.4 A1 N2
[3 marks]
Total [7 marks]