Date | November 2014 | Marks available | 2 | Reference code | 14N.2.sl.TZ0.1 |
Level | SL only | Paper | 2 | Time zone | TZ0 |
Command term | Find | Question number | 1 | Adapted from | N/A |
Question
Let f(x)=2x+3 and g(x)=x3.
Find (f∘g)(x).
Solve the equation (f∘g)(x)=0.
Markscheme
attempt to form composite (in any order) (M1)
egf(x3), (2x+3)3
(f∘g)(x)=2x3+3 A1 N2
[2 marks]
evidence of appropriate approach (M1)
eg2x3=−3, sketch
correct working (A1)
egx3=−32, sketch
−1.14471
x=3√−32(exact), −1.14 [−1.15, −1.14] A1 N3
[3 marks]
Total [5 marks]
Examiners report
Generally well done, though there were some careless errors with the substitution into f in part (ai) and rearranging the equation in part (b). Although candidates understood that they were supposed to solve the equation 2x3+3=0, many wrote 2x3=3 or x=√32. The majority of the candidates chose an algebraic method instead of using their GDC.
Generally well done, though there were some careless errors with the substitution into f in part (ai) and rearranging the equation in part (b). Although candidates understood that they were supposed to solve the equation 2x3+3=0, many wrote 2x3=3 or x=√32. The majority of the candidates chose an algebraic method instead of using their GDC.