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Date May 2017 Marks available 6 Reference code 17M.1.SL.TZ2.S_5
Level Standard Level Paper Paper 1 Time zone Time zone 2
Command term Find Question number S_5 Adapted from N/A

Question

Let f ( x ) = 3 x 2 ( x 3 + 1 ) 5 . Given that f ( 0 ) = 1 , find f ( x ) .

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

valid approach     (M1)

eg f d x ,   3 x 2 ( x 3 + 1 ) 5 d x

correct integration by substitution/inspection     A2

eg f ( x ) = 1 4 ( x 3 + 1 ) 4 + c ,   1 4 ( x 3 + 1 ) 4

correct substitution into their integrated function (must include c )     M1

eg 1 = 1 4 ( 0 3 + 1 ) 4 + c ,   1 4 + c = 1

 

Note:     Award M0 if candidates substitute into f or f .

 

c = 5 4     (A1)

f ( x ) = 1 4 ( x 3 + 1 ) 4 + 5 4   ( = 1 4 ( x 3 + 1 ) 4 + 5 4 ,   5 ( x 3 + 1 ) 4 1 4 ( x 3 + 1 ) 4 )     A1     N4

[6 marks]

Examiners report

[N/A]

Syllabus sections

Topic 5—Calculus » AHL 5.11—Indefinite integration, reverse chain, by substitution
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