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Date November 2018 Marks available 7 Reference code 18N.2.AHL.TZ0.H_2
Level Additional Higher Level Paper Paper 2 Time zone Time zone 0
Command term Find Question number H_2 Adapted from N/A

Question

A function f satisfies the conditions f(0)=4f(1)=0 and its second derivative is f(x)=15x+1(x+1)2, x ≥ 0.

Find f(x).

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

f(x)=(15x+1(x+1)2)dx=10x321x+1(+c)      (M1)A1A1

Note: A1 for first term, A1 for second term. Withhold one A1 if extra terms are seen.

 

f(x)=(10x321x+1+c)dx=4x52ln(x+1)+cx+d     A1

Note: Allow FT from incorrect f(x) if it is of the form f(x)=Ax32+Bx+1+c.

Accept ln|x+1|.

 

attempt to use at least one boundary condition in their f(x)      (M1)

x=0y=4

⇒ d=4      A1

x=1y=0

⇒ 0=4ln2+c4

⇒  c=ln2(=0.693)      A1

f(x)=4x52ln(x+1)+xln24

 

[7 marks]

Examiners report

[N/A]

Syllabus sections

Topic 5—Calculus » AHL 5.11—Indefinite integration, reverse chain, by substitution
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Topic 5—Calculus

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