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Date May 2018 Marks available 3 Reference code 18M.1.SL.TZ2.S_1
Level Standard Level Paper Paper 1 Time zone Time zone 2
Command term Find Question number S_1 Adapted from N/A

Question

Let OA=(213) and AB=(131), where O is the origin. L1 is the line that passes through A and B.

Find a vector equation for L1.

[2]
a.

The vector (2p0) is perpendicular to AB. Find the value of p.

[3]
b.

Markscheme

* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.

any correct equation in the form r = a + tb (accept any parameter for t)

where a is (213), and b is a scalar multiple of (131)     A2 N2

eg r = (213)=t(131)r = 2i + j + 3k + s(i + 3j + k)

Note: Award A1 for the form a + tb, A1 for the form L = a + tb, A0 for the form r = b + ta.

[2 marks]

a.

METHOD 1

correct scalar product     (A1)

eg  (1 × 2) + (3 × p) + (1 × 0), 2 + 3p

evidence of equating their scalar product to zero     (M1)

eg  a•b = 0, 2 + 3p = 0, 3p = −2

p=23       A1 N3

 

METHOD 2

valid attempt to find angle between vectors      (M1)

correct substitution into numerator and/or angle       (A1)

eg  cosθ=(1×2)+(3×p)+(1×0)|a||b|,cosθ=0

p=23       A1 N3

[3 marks]

b.

Examiners report

[N/A]
a.
[N/A]
b.

Syllabus sections

Topic 3—Geometry and trigonometry » AHL 3.11—Vector equation of a line in 2d and 3d
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Topic 3—Geometry and trigonometry » AHL 3.13—Scalar and vector products
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