Date | November 2021 | Marks available | 1 | Reference code | 21N.1.AHL.TZ0.2 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Write down | Question number | 2 | Adapted from | N/A |
Question
The function f is defined by f(x)=2x+43-x, where x∈ℝ, x≠3.
Write down the equation of
Find the coordinates where the graph of f crosses
the vertical asymptote of the graph of f.
the horizontal asymptote of the graph of f.
the x-axis.
the y-axis.
Sketch the graph of f on the axes below.
The function g is defined by g(x)=ax+43-x, where x∈ℝ, x≠3 and a∈ℝ.
Given that g(x)=g-1(x), determine the value of a.
Markscheme
x=3 A1
[1 mark]
y=-2 A1
[1 mark]
(-2, 0) (accept x=-2) A1
[1 mark]
(0, 43) (accept y=43 and f(0)=43) A1
[1 mark]
A1
Note: Award A1 for completely correct shape: two branches in correct quadrants with asymptotic behaviour.
[1 mark]
METHOD 1
(g(x)=)y=ax+43-x
attempt to find x in terms of y (M1)
OR exchange x and y and attempt to find y in terms of x
3y-xy=ax+4 A1
ax+xy=3y-4
x(a+y)=3y-4
x=3y-4y+a
g-1(x)=3x-4x+a A1
Note: Condone use of y=
g(x)≡g-1(x)
ax+43-x≡3x-4x+a
⇒a=-3 A1
METHOD 2
g(x)=ax+43-x
attempt to find an expression for g(g(x)) and equate to x (M1)
gg(x)=a(ax+43-x)+43-(ax+43-x)=x A1
a(ax+4)+4(3-x)(9-3x)-(ax+4)=x
a(ax+4)+4(3-x)5-(3+a)x=x
a(ax+4)+4(3-x)=x(5-(3+a)x) A1
equating coefficients of x2 (or similar)
a=-3 A1
[4 marks]