Date | November 2019 | Marks available | 8 | Reference code | 19N.1.SL.TZ0.S_6 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Find | Question number | S_6 | Adapted from | N/A |
Question
Let f(x)=4cos(x2)+1, for 0⩽x⩽6π. Find the values of x for which f(x)>2√2+1.
Markscheme
METHOD 1 – FINDING INTERVALS FOR x
4cos(x2)+1>2√2+1
correct working (A1)
eg 4cos(x2)=2√2, cos(x2)>√22
recognizing cos−1√22=π4 (A1)
one additional correct value for x2 (ignoring domain and equation/inequalities) (A1)
eg −π4, 7π4, 315∘, 9π4, −45∘, 15π4
three correct values for x A1A1
eg π2, 7π2, 9π2
valid approach to find intervals (M1)
eg
correct intervals (must be in radians) A1A1 N2
0⩽x<π2, 7π2<x<9π2
Note: If working shown, award A1A0 if inclusion/exclusion of endpoints is incorrect. If no working shown award N1.
If working shown, award A1A0 if both correct intervals are given, and additional intervals are given. If no working shown award N1.
Award A0A0 if inclusion/exclusion of endpoints are incorrect and additional intervals are given.
METHOD 2 – FINDING INTERVALS FOR x2
4cos(x2)+1>2√2+1
correct working (A1)
eg 4cos(x2)=2√2, cos(x2)>√22
recognizing cos−1√22=π4 (A1)
one additional correct value for x2 (ignoring domain and equation/inequalities) (A1)
eg −π4, 7π4, 315∘, 9π4, −45∘, 15π4
three correct values for x2 A1
eg π4, 7π4, 9π4
valid approach to find intervals (M1)
eg
one correct interval for x2 A1
eg 0⩽x2<π4, 7π4<x2<9π4
correct intervals (must be in radians) A1A1 N2
0⩽x<π2, 7π2<x<9π2
Note: If working shown, award A1A0 if inclusion/exclusion of endpoints is incorrect. If no working shown award N1.
If working shown, award A1A0 if both correct intervals are given, and additional intervals are given. If no working shown award N1.
Award A0A0 if inclusion/exclusion of endpoints are incorrect and additional intervals are given.
[8 marks]