Date | May 2019 | Marks available | 1 | Reference code | 19M.1.AHL.TZ1.H_8 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 1 |
Command term | Write down | Question number | H_8 | Adapted from | N/A |
Question
The graph of y=f′(x), 0 ≤ x ≤ 5 is shown in the following diagram. The curve intercepts the x-axis at (1, 0) and (4, 0) and has a local minimum at (3, −1).
The shaded area enclosed by the curve y=f′(x), the x-axis and the y-axis is 0.5. Given that f(0)=3,
The area enclosed by the curve y=f′(x) and the x-axis between x=1 and x=4 is 2.5 .
Write down the x-coordinate of the point of inflexion on the graph of y=f(x).
find the value of f(1).
find the value of f(4).
Sketch the curve y=f(x), 0 ≤ x ≤ 5 indicating clearly the coordinates of the maximum and minimum points and any intercepts with the coordinate axes.
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
3 A1
[1 mark]
attempt to use definite integral of f′(x) (M1)
∫10f′(x)dx=0.5
f(1)−f(0)=0.5 (A1)
f(1)=0.5+3
= 3.5 A1
[3 marks]
∫41f′(x)dx=−2.5 (A1)
Note: (A1) is for −2.5.
f(4)−f(1)=−2.5
f(4)=3.5−2.5
= 1 A1
[2 marks]
A1A1A1
A1 for correct shape over approximately the correct domain
A1 for maximum and minimum (coordinates or horizontal lines from 3.5 and 1 are required),
A1 for y-intercept at 3
[3 marks]