Date | May Example questions | Marks available | 1 | Reference code | EXM.1.AHL.TZ0.2 |
Level | Additional Higher Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Explain | Question number | 2 | Adapted from | N/A |
Question
Consider the integral for .
Very briefly, explain why the value of this integral must be negative.
[1]
a.
Express the function in partial fractions.
[6]
b.
Use parts (a) and (b) to show that .
[4]
c.
Markscheme
The numerator is negative but the denominator is positive. Thus the integrand is negative and so the value of the integral will be negative. R1AG
[1 mark]
a.
M1M1A1
M1A1
A1
[6 marks]
b.
M1A1A1
Hence R1AG
[4 marks]
c.
Examiners report
[N/A]
a.
[N/A]
b.
[N/A]
c.