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Date November 2021 Marks available 3 Reference code 21N.2.HL.TZ0.7
Level Higher level Paper Paper 2 Time zone 0 - no time zone
Command term Predict Question number 7 Adapted from N/A

Question

A conducting sphere has radius 48 cm. The electric potential on the surface of the sphere is 3.4 × 105 V.

The sphere is connected by a long conducting wire to a second conducting sphere of radius 24 cm. The second sphere is initially uncharged.

 

Show that the charge on the surface of the sphere is +18 μC.

[1]
a.

Describe, in terms of electron flow, how the smaller sphere becomes charged.

[1]
b.i.

Predict the charge on each sphere.

[3]
b.ii.

Markscheme

Q=«VRk=»3.4×105×0.488.99×109

OR

Q=18.2 «μC» ✓

a.

electrons leave the small sphere «making it positively charged» ✓

b.i.

kq148=kq224q1=2q2 ✓

q1+q2=18 ✓

so q1=12 «μC», q2=6.0 «μC» ✓

 

Award [3] marks for a bald correct answer.

b.ii.

Examiners report

[N/A]
a.
[N/A]
b.i.
[N/A]
b.ii.

Syllabus sections

Additional higher level (AHL) » Topic 10: Fields » 10.2 – Fields at work
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