Date | November 2018 | Marks available | 1 | Reference code | 18N.2.HL.TZ0.7 |
Level | Higher level | Paper | Paper 2 | Time zone | 0 - no time zone |
Command term | Determine | Question number | 7 | Adapted from | N/A |
Question
A small electric motor is used with a 12 mF capacitor and a battery in a school experiment.
When the switch is connected to X, the capacitor is charged using the battery. When the switch is connected to Y, the capacitor fully discharges through the electric motor that raises a small mass.
The battery has an emf of 7.5 V. Determine the charge that flows through the motor when the mass is raised.
The motor can transfer one-third of the electrical energy stored in the capacitor into gravitational potential energy of the mass. Determine the maximum height through which a mass of 45 g can be raised.
An additional identical capacitor is connected in series with the first capacitor and the charging and discharging processes are repeated. Comment on the effect this change has on the height and time taken to raise the 45 g mass.
Markscheme
charge stored on capacitor = 12 × 10−3 × 7.5 = 0.09 «C» ✔
energy stored in capacitor «CV2 or QV =» × 12 × 10−3 × 7.52 «= 0.338 J» ✔
height = «» 0.25/0.26 «m»
Allow use of g = 10 m s−2 which gives 0.25 «m»
C halved ✔
so energy stored is halved/reduced so rises «less than» half height ✔
discharge time/raise time less as RC halved/reduced ✔
Allow 6 mF