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Date November 2018 Marks available 1 Reference code 18N.2.sl.TZ0.2
Level SL Paper 2 Time zone TZ0
Command term Classify Question number 2 Adapted from N/A

Question

Propan-2-ol is a useful organic solvent.

Draw the structural formula of propan-2-ol.

[1]
a.

Calculate the number of hydrogen atoms in 1.00 g of propan-2-ol.

[2]
b.

Classify propan-2-ol as a primary, secondary or tertiary alcohol, giving a reason.

[1]
c.

State a suitable oxidizing agent for the oxidation of propan-2-ol in an acidified aqueous solution.

[1]
d.i.

Deduce the average oxidation state of carbon in propan-2-ol.

[1]
d.ii.

Deduce the product of the oxidation of propan-2-ol with the oxidizing agent in (d)(i).

[1]
d.iii.

Markscheme

CH3CH(OH)CH3

 

Accept the full or condensed structural formula.

a.

« 1.00 g ( 12.01 × 3 + 1.01 × 8 + 16.00 ) g mo l 1 = »  0.0166  «mol CH3CH(OH)CH3» 

«0.0166 mol × 6.02 × 1023 molecules mol−1 × 8 atoms molecule−1 =» 8.01 × 1022 «atoms of hydrogen» ✔ 

 

Accept answers in the range 7.99 × 1022 to 8.19 × 1022.

Award [2] for correct final answer.

b.

secondary AND OH/hydroxyl is attached to a carbon bonded to one hydrogen

OR

secondary AND OH/hydroxyl is attached to a carbon bonded to two C/R/alkyl/CH3 «groups» ✔

 

Accept “secondary AND OH is attached to the second carbon in the chain”.

c.

«potassium/sodium» manganate(VII)/permanganate/KMnO4/NaMnO4/MnO4

OR

«potassium/sodium» dichromate(VI)/K2Cr2O7/Na2Cr2O7/Cr2O72− ✔

d.i.

−2 ✔

d.ii.

propanone/propan-2-one/CH3COCH3

d.iii.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.
[N/A]
d.i.
[N/A]
d.ii.
[N/A]
d.iii.

Syllabus sections

Core » Topic 10: Organic chemistry » 10.1 Fundamentals of organic chemistry
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