DP Mathematics HL Questionbank

8.12
Description
[N/A]Directly related questions
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 17N.3srg.hl.TZ0.5b: Prove that Ker(f) is a subgroup of {G, ∗}.
- 17N.3srg.hl.TZ0.5a: Prove that f(eG)=eH.
- 17M.3srg.hl.TZ0.4d: Show that the groups {Z, ∗} and...
- 15N.3srg.hl.TZ0.5c: Prove that {Ker(f), +} is a subgroup of...
- 15N.3srg.hl.TZ0.5b: Find the kernel of f.
- 15N.3srg.hl.TZ0.5a: Prove that the function f is a homomorphism from the group...
- 12N.3srg.hl.TZ0.3d: Is {P(A), Δ} isomorphic to {Z4, +4} ?...
- 08M.3srg.hl.TZ1.3: (a) Find the six roots of the equation z6−1=0 , giving your answers in the form...
- 11M.3srg.hl.TZ0.5b: Consider the group G , of order 4, which has distinct elements a , b and c and the identity...
- SPNone.3srg.hl.TZ0.3b: The group {K, ∘} is defined on the six permutations of the integers 1, 2,...
- SPNone.3srg.hl.TZ0.4: The groups {K, ∗} and {H, ⊙} are defined by the...
- 10M.3srg.hl.TZ0.3: (a) Consider the set A = {1, 3, 5, 7} under the binary operation ∗, where ∗...
- 10N.3srg.hl.TZ0.4: Set...
- 11N.3srg.hl.TZ0.1c: Show that {G, ×16} and {H, ∗} are not isomorphic.
- 14M.3srg.hl.TZ0.4b: (i) Prove that the kernel of f, K=Ker(f), is closed under the group...
- 14M.3srg.hl.TZ0.4a: Prove that f(eG)=eH, where eG is the identity element in G and eH...
- 15M.3srg.hl.TZ0.5c: The mapping ϕ:G→G is given by ϕ(g)=g+g, for g∈G. Prove that...
- 14N.3srg.hl.TZ0.4c: Given that f(x∗y)=p, find f(y).
- 14N.3srg.hl.TZ0.4a: Prove that for all a∈G, f(a−1)=(f(a))−1.
- 14N.3srg.hl.TZ0.4b: Let {H, ∘} be the cyclic group of order seven, and let p be a...
Sub sections and their related questions
Definition of a group homomorphism.
- SPNone.3srg.hl.TZ0.4: The groups {K, ∗} and {H, ⊙} are defined by the...
- 14M.3srg.hl.TZ0.4b: (i) Prove that the kernel of f, K=Ker(f), is closed under the group...
- 14M.3srg.hl.TZ0.4a: Prove that f(eG)=eH, where eG is the identity element in G and eH...
- 14N.3srg.hl.TZ0.4a: Prove that for all a∈G, f(a−1)=(f(a))−1.
- 14N.3srg.hl.TZ0.4b: Let {H, ∘} be the cyclic group of order seven, and let p be a...
- 14N.3srg.hl.TZ0.4c: Given that f(x∗y)=p, find f(y).
- 15N.3srg.hl.TZ0.5a: Prove that the function f is a homomorphism from the group...
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...
Definition of the kernel of a homomorphism.
- 14M.3srg.hl.TZ0.4b: (i) Prove that the kernel of f, K=Ker(f), is closed under the group...
- 14M.3srg.hl.TZ0.4a: Prove that f(eG)=eH, where eG is the identity element in G and eH...
- 15N.3srg.hl.TZ0.5b: Find the kernel of f.
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...
Proof that the kernel and range of a homomorphism are subgroups.
- 15N.3srg.hl.TZ0.5c: Prove that {Ker(f), +} is a subgroup of...
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...
Proof of homomorphism properties for identities and inverses.
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...
Isomorphism of groups.
- 12N.3srg.hl.TZ0.3d: Is {P(A), Δ} isomorphic to {Z4, +4} ?...
- 08M.3srg.hl.TZ1.3: (a) Find the six roots of the equation z6−1=0 , giving your answers in the form...
- 11M.3srg.hl.TZ0.5b: Consider the group G , of order 4, which has distinct elements a , b and c and the identity...
- SPNone.3srg.hl.TZ0.3b: The group {K, ∘} is defined on the six permutations of the integers 1, 2,...
- 10M.3srg.hl.TZ0.3: (a) Consider the set A = {1, 3, 5, 7} under the binary operation ∗, where ∗...
- 10N.3srg.hl.TZ0.4: Set...
- 11N.3srg.hl.TZ0.1c: Show that {G, ×16} and {H, ∗} are not isomorphic.
- 15M.3srg.hl.TZ0.5c: The mapping ϕ:G→G is given by ϕ(g)=g+g, for g∈G. Prove that...
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...
The order of an element is unchanged by an isomorphism.
- 16M.3srg.hl.TZ0.3: The group {G, ∗} is Abelian and the bijection f: G→G is...
- 18M.3srg.hl.TZ0.4c: Let f:S4→S4 be defined by f(p)=p∘p...