Date | May 2010 | Marks available | 6 | Reference code | 10M.2.hl.TZ2.6 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
The random variable X follows a Poisson distribution with mean λ.
(a) Find λ if P(X=0)+P(X=1)=0.123.
(b) With this value of λ, find P(0<X<9).
Markscheme
(a) required to solve e−λ+λe−λ=0.123 M1A1
solving to obtain λ=3.63 A2 N2
Note: Award A2 if an additional negative solution is seen but A0 if only a negative solution is seen.
(b) P(0<X<9)
=P(X⩽8)−P(X=0) (or equivalent) (M1)
=0.961 A1
[6 marks]
Examiners report
Part (a) - Well done by most, although there were some answers that ignored the requirement of mathematical notation.
Part (b) - Not successfully answered by many. The main problem was not correctly interpreting the inequalities in the probability.