Date | May 2010 | Marks available | 6 | Reference code | 10M.2.hl.TZ2.6 |
Level | HL only | Paper | 2 | Time zone | TZ2 |
Command term | Find | Question number | 6 | Adapted from | N/A |
Question
The random variable X follows a Poisson distribution with mean \(\lambda \).
(a) Find \(\lambda \) if \({\text{P}}(X = 0) + {\text{P}}(X = 1) = 0.123\).
(b) With this value of \(\lambda \), find \({\text{P}}(0 < X < 9)\).
Markscheme
(a) required to solve \({{\text{e}}^{ - \lambda }} + \lambda {{\text{e}}^{ - \lambda }} = 0.123\) M1A1
solving to obtain \(\lambda = 3.63\) A2 N2
Note: Award A2 if an additional negative solution is seen but A0 if only a negative solution is seen.
(b) \({\text{P}}(0 < X < 9)\)
\( = {\text{P}}(X \leqslant 8) - {\text{P}}(X = 0)\) (or equivalent) (M1)
\( = 0.961\) A1
[6 marks]
Examiners report
Part (a) - Well done by most, although there were some answers that ignored the requirement of mathematical notation.
Part (b) - Not successfully answered by many. The main problem was not correctly interpreting the inequalities in the probability.