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Date May 2008 Marks available 6 Reference code 08M.1.hl.TZ2.4
Level HL only Paper 1 Time zone TZ2
Command term Find Question number 4 Adapted from N/A

Question

Let f(x)=4x+2, x2 and g(x)=x1.

If h=gf , find

(a)     h(x) ;

(b)     h1(x) , where h1 is the inverse of h.

Markscheme

(a)     h(x)=g(4x+2)     (M1)

=4x+21(=2x2+x)     A1

 

(b)     METHOD 1

x=4y+21(interchanging x and y)     M1

Attempting to solve for y     M1

(y+2)(x+1)=4(y+2=4x+1)     (A1)

h1(x)=4x+12(x1)     A1     N1

METHOD 2

x=2y2+y(interchanging x and y)     M1

Attempting to solve for y     M1

xy+y=22x(y(x+1)=2(1x))     (A1)

h1(x)=2(1x)x+1(x1)     A1     N1

Note: In either METHOD 1 or METHOD 2 rearranging first and interchanging afterwards is equally acceptable.

 

[6 marks]

Examiners report

This question was generally well done, with very few candidates calculating fg rather than gf.

Syllabus sections

Topic 2 - Core: Functions and equations » 2.1 » Composite functions fg .

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