Date | May 2018 | Marks available | 5 | Reference code | 18M.2.hl.TZ1.6 |
Level | HL only | Paper | 2 | Time zone | TZ1 |
Command term | Calculate | Question number | 6 | Adapted from | N/A |
Question
The mean number of squirrels in a certain area is known to be 3.2 squirrels per hectare of woodland. Within this area, there is a 56 hectare woodland nature reserve. It is known that there are currently at least 168 squirrels in this reserve.
Assuming the population of squirrels follow a Poisson distribution, calculate the probability that there are more than 190 squirrels in the reserve.
Markscheme
X is number of squirrels in reserve
X ∼ Po(179.2) A1
Note: Award A1 if 179.2 or 56 × 3.2 seen or implicit in future calculations.
recognising conditional probability M1
P(X > 190 | X ≥ 168)
\( = \frac{{{\text{P}}\left( {X > 190} \right)}}{{{\text{P}}\left( {X \geqslant 168} \right)}} = \left( {\frac{{0.19827 \ldots }}{{0.80817 \ldots }}} \right)\) (A1)(A1)
= 0.245 A1
[5 marks]