Date | May 2014 | Marks available | 6 | Reference code | 14M.1.hl.TZ2.1 |
Level | HL only | Paper | 1 | Time zone | TZ2 |
Command term | Find and State | Question number | 1 | Adapted from | N/A |
Question
Events \(A\) and \(B\) are such that \({\text{P}}(A) = \frac{2}{5},{\text{ P}}(B) = \frac{{11}}{{20}}\) and \({\text{P}}(A|B) = \frac{2}{{11}}\).
(a) Find \({\text{P}}(A \cap B)\).
(b) Find \({\text{P}}(A \cup B)\).
(c) State with a reason whether or not events \(A\) and \(B\) are independent.
Markscheme
(a) \({\text{P}}(A \cap B) = {\text{P}}(A|B) \times P(B)\)
\({\text{P}}(A \cap B) = \frac{2}{{11}} \times \frac{{11}}{{20}}\) (M1)
\( = \frac{1}{{10}}\) A1
[2 marks]
(b) \({\text{P}}(A \cup B) = {\text{P}}(A) + {\text{P}}(B) - {\text{P}}(A \cap B)\)
\({\text{P}}(A \cup B) = \frac{2}{5} + \frac{{11}}{{20}} - \frac{1}{{10}}\) (M1)
\( = \frac{{17}}{{20}}\) A1
[2 marks]
(c) No – events A and B are not independent A1
EITHER
\({\text{P}}(A|B) \ne {\text{P}}(A)\) R1
\(\left( {\frac{2}{{11}} \ne \frac{2}{5}} \right)\)
OR
\({\text{P}}(A) \times {\text{P}}(B) \ne {\text{P}}(A \cap B)\)
\(\frac{2}{5} \times \frac{{11}}{{20}} = \frac{{11}}{{50}} \ne \frac{1}{{10}}\) R1
Note: The numbers are required to gain R1 in the ‘OR’ method only.
Note: Do not award A1R0 in either method.
[2 marks]
Total [6 marks]