Date | May 2013 | Marks available | [N/A] | Reference code | 13M.3.hl.TZ1.E4 |
Level | HL | Paper | 3 | Time zone | TZ1 |
Command term | State | Question number | E4 | Adapted from | N/A |
Question
Heavy metal ions are pollutants that can be removed in the tertiary stage of waste water treatment.
A water sample at 25 °C contains lead and sulfate ions in the following concentrations:
\[\begin{array}{*{20}{l}} {[{\text{P}}{{\text{b}}^{2 + }}] = 2.32 \times {{10}^{ - 6}}{\text{ mol}}\,{\text{d}}{{\text{m}}^{ - 3}}} \\ {[{\text{SO}}_4^{2 - }] = 4.15 \times {{10}^{ - 3}}{\text{ mol}}\,{\text{d}}{{\text{m}}^{ - 3}}} \end{array}\]
The solubility product constant, \({K_{{\text{sp}}}}\), of lead sulfate is \(1.80 \times {10^{ - 8}}\) at 25 °C.
State the expression for the solubility product constant, \({K_{{\text{sp}}}}\), of lead sulfate.
Deduce why lead sulfate will not precipitate out of the water sample at these concentrations.
Some magnesium sulfate is added to the water sample. Determine the increase in sulfate ion concentration needed for lead sulfate to precipitate.
Markscheme
\(({K_{{\text{sp}}}} = ){\text{ }}[{\text{P}}{{\text{b}}^{2 + }}][{\text{SO}}_4^{2 - }]\);
\([{\text{P}}{{\text{b}}^{2 + }}][{\text{SO}}_4^{2 - }]/2.32 \times {10^{ - 6}} \times 4.15 \times {10^{ - 3}}/9.63 \times {10^{ - 9}}\) is less than \({K_{{\text{sp}}}}/1.80 \times {10^{ - 8}}\);
\((1.80 \times {10^{ - 8}} = 2.32 \times {10^{ - 6}} \times [{\text{SO}}_4^{2 - }]),{\text{ }}[{\text{SO}}_4^{2 - }] = 7.76 \times {10^{ - 3}}{\text{ (mol}}\,{\text{d}}{{\text{m}}^{ - 3}}{\text{)}}\);
increase in \([{\text{SO}}_4^{2 - }]{\text{ }}( = 7.76 \times {10^{ - 3}} - 4.15 \times {10^{ - 3}}) = 3.61 \times {10^{ - 3}}{\text{ }}({\text{mol}}\,{\text{d}}{{\text{m}}^{ - 3}})\);
Award [2] for correct final answer.
Examiners report
It was very surprising in (a) at the number of candidates who simply could not write a correct \({K_{{\text{sp}}}}\) expression for lead sulfate.
Only the stronger candidates got (b) and subsequently (c) correct.
Only the stronger candidates got (b) and subsequently (c) correct.