Date | May 2016 | Marks available | 1 | Reference code | 16M.3.sl.TZ0.3 |
Level | SL | Paper | 3 | Time zone | TZ0 |
Command term | State | Question number | 3 | Adapted from | N/A |
Question
Iron may be extracted from an ore containing Fe2O3 in a blast furnace by reaction with coke, limestone and air. Aluminium is obtained by electrolysis of an ore containing Al2O3.
State the overall redox equation when carbon monoxide reduces Fe2O3 to Fe.
Predict the magnetic properties of Fe2O3 and Al2O3 in terms of the electron structure of the metal ion, giving your reasons.
Fe2O3:
Al2O3:
Molten alumina, Al2O3(l), was electrolysed by passing 2.00×106 C through the cell. Calculate the mass of aluminium produced, using sections 2 and 6 of the data booklet.
Markscheme
Fe2O3 (s) + 3CO (g) → 2Fe (l) + 3CO2 (g)
Fe2O3:
paramagnetic
AND
unpaired electrons present «so magnetic moments do not cancel out»
Al2O3:
diamagnetic
AND
no unpaired electrons/all electrons are paired «so magnetic moments cancel out»
Award [1 max] for “Fe2O3 paramagnetic AND Al2O3 diamagnetic”.
Award [1 max] for “Fe2O3 unpaired electrons present AND Al2O3 no unpaired electrons/all electrons are paired”.
Award [1 max] for “Magnetic moments do not cancel out in Fe2O3 but do in Al2O3”.
Unpaired and paired electrons may also be conveyed by orbital diagrams for the respective ions.
\(n\left( {\rm{e}} \right) = \frac{{2.00 \times {{10}^6}}}{{96500}}/20.7 \ll {\rm{mol}} \gg \)
OR
n(Al)=\(\frac{1}{3}\)n(e)/6.91«mol»
m(Al)=«6.91×26.98=»186«g»
Award [2] for correct final answer for any value within the range 186–189 «g».