Date | May 2008 | Marks available | 3 | Reference code | 08M.1.sl.TZ2.3 |
Level | SL only | Paper | 1 | Time zone | TZ2 |
Command term | Find and Sketch | Question number | 3 | Adapted from | N/A |
Question
Triangle ABC is drawn such that angle ABC is 90∘, angle ACB is 60∘ and AB is 7.3 cm.
(i) Sketch a diagram to illustrate this information. Label the points A, B, C. Show the angles 90∘, 60∘ and the length 7.3 cm on your diagram.
(ii) Find the length of BC.
Point D is on the straight line AC extended and is such that angle CDB is 20∘.
(i) Show the point D and the angle 20∘ on your diagram.
(ii) Find the size of angle CBD.
Markscheme
Unit penalty (UP) is applicable where indicated in the left hand column.
(i)
(A1)
For A, B, C, 7.3, 60∘, 90∘, shown in correct places (A1)
Note: The 90∘ should look like 90∘ (allow ±10∘)
(ii) Using tan60 or tan30 (M1)
(UP) 4.21 cm (A1)(ft)
Note: (ft) on their diagram
Or
Using sine rule with their correct values (M1)
(UP) =4.21 cm (A1)(ft)
Or
Using special triangle 7.3√3 (M1)
(UP) 4.21 cm (A1)(ft)
Or
Any other valid solution
Note: If A and B are swapped then BC=8.43 cm (C3)
[3 marks]
(i) For ACD in a straight line and all joined up to B, for 20∘ shown in correct place and D labelled. D must be on AC extended. (A1)
(ii) BˆCD=120∘ (A1)
CˆBD=40∘ (A1) (C3)
[3 marks]
Examiners report
The initial diagram was well drawn by most candidates but few could extend AC to find D. The point D was either drawn between A and C or on CA extended. When on CA extended the candidates could be awarded A1 follow through for the angle. A surprising number of candidates could not find the correct answer for the length of BC.
The initial diagram was well drawn by most candidates but few could extend AC to find D. The point D was either drawn between A and C or on CA extended. When on CA extended the candidates could be awarded A1 follow through for the angle. A surprising number of candidates could not find the correct answer for the length of BC.