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Date November 2017 Marks available 2 Reference code 17N.1.sl.TZ0.10
Level SL only Paper 1 Time zone TZ0
Command term Find Question number 10 Adapted from N/A

Question

Emily’s kite ABCD is hanging in a tree. The plane ABCDE is vertical.

Emily stands at point E at some distance from the tree, such that EAD is a straight line and angle BED = 7°. Emily knows BD = 1.2 metres and angle BDA = 53°, as shown in the diagram

N17/5/MATSD/SP1/ENG/TZ0/10

T is a point at the base of the tree. ET is a horizontal line. The angle of elevation of A from E is 41°.

Find the length of EB.

[3]
a.

Write down the angle of elevation of B from E.

[1]
b.

Find the vertical height of B above the ground.

[2]
c.

Markscheme

Units are required in parts (a) and (c).

EBsin53=1.2sin7     (M1)(A1)

 

Note:     Award (M1) for substitution into sine formula, (A1) for correct substitution.

 

(EB=) 7.86 mOR786 cm (7.86385 mOR786.385 cm)     (A1)     (C3)

[3 marks]

a.

34°     (A1)     (C1)

[1 mark]

b.

Units are required in parts (a) and (c).

sin34=height7.86385     (M1)

 

Note:     Award (M1) for correct substitution into a trigonometric ratio.

 

(height=) 4.40 mOR440 cm (4.39741 mOR439.741 cm)     (A1)(ft)     (C2)

 

Note:     Accept “BT” used for height. Follow through from parts (a) and (b). Use of 7.86 gives an answer of 4.39525….

 

[2 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 5 - Geometry and trigonometry » 5.3 » Use of the sine rule: asinA=bsinB=csinC.
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