Date | May 2008 | Marks available | 2 | Reference code | 08M.1.sl.TZ1.8 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Calculate | Question number | 8 | Adapted from | N/A |
Question
The first term of an arithmetic sequence is 0 and the common difference is 12.
Find the value of the 96th term of the sequence.
The first term of a geometric sequence is 6. The 6th term of the geometric sequence is equal to the 17th term of the arithmetic sequence given above.
Write down an equation using this information.
The first term of a geometric sequence is 6. The \6th term of the geometric sequence is equal to the 17th term of the arithmetic sequence given above.
Calculate the common ratio of the geometric sequence.
Markscheme
u96=u1+95d (M1)
=0+95×12
=1140 (A1) (C2)
[2 marks]
6r5=16d (A1)
6r5=16×12 (192) (A1) (C2)
Note: (A1) only, if both terms seen without an equation.
[2 marks]
r5=32 (A1)(ft)
Note: (ft) from their (b).
r=2 (A1)(ft) (C2)
[2 marks]
Examiners report
Part (a) was done well. There was some confusion in answering part (b) with many candidates unsure what they needed to write down. Often the two terms were seen somewhere in the working without the equation being written down in the answer box, or the equation was seen in the working for part (c). Part (c) was answered well, often with follow-through marks being awarded from an incorrect part (b) provided the working was seen.
Part (a) was done well. There was some confusion in answering part (b) with many candidates unsure what they needed to write down. Often the two terms were seen somewhere in the working without the equation being written down in the answer box, or the equation was seen in the working for part (c). Part (c) was answered well, often with follow-through marks being awarded from an incorrect part (b) provided the working was seen.
Part (a) was done well. There was some confusion in answering part (b) with many candidates unsure what they needed to write down. Often the two terms were seen somewhere in the working without the equation being written down in the answer box, or the equation was seen in the working for part (c). Part (c) was answered well, often with follow-through marks being awarded from an incorrect part (b) provided the working was seen.