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Date May 2017 Marks available 2 Reference code 17M.1.sl.TZ1.10
Level SL only Paper 1 Time zone TZ1
Command term Find Question number 10 Adapted from N/A

Question

The first three terms of a geometric sequence are u1=486, u2=162, u3=54.

Find the value of r, the common ratio of the sequence.

[2]
a.

Find the value of n for which un=2.

[2]
b.

Find the sum of the first 30 terms of the sequence.

[2]
c.

Markscheme

162486OR54162     (M1)

 

Note:     Award (M1) for dividing any un+1 by un.

 

=13 (0.333, 0.333333)     (A1)     (C2)

[2 marks]

a.

486(13)n1=2     (M1)

 

Note:     Award (M1) for their correct substitution into geometric sequence formula.

 

n=6     (A1)(ft)     (C2)

 

Note:     Follow through from part (a).

Award (A1)(A0) for u6=2 or u6 with or without working.

 

[2 marks]

b.

S30=486(11330)113     (M1)

 

Note:     Award (M1) for correct substitution into geometric series formula.

 

=729     (A1)(ft)     (C2)

[2 marks]

c.

Examiners report

[N/A]
a.
[N/A]
b.
[N/A]
c.

Syllabus sections

Topic 1 - Number and algebra » 1.8 » Geometric sequences and series.
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