Date | May 2017 | Marks available | 2 | Reference code | 17M.1.sl.TZ1.10 |
Level | SL only | Paper | 1 | Time zone | TZ1 |
Command term | Find | Question number | 10 | Adapted from | N/A |
Question
The first three terms of a geometric sequence are u1=486, u2=162, u3=54.
Find the value of r, the common ratio of the sequence.
Find the value of n for which un=2.
Find the sum of the first 30 terms of the sequence.
Markscheme
162486OR54162 (M1)
Note: Award (M1) for dividing any un+1 by un.
=13 (0.333, 0.333333…) (A1) (C2)
[2 marks]
486(13)n−1=2 (M1)
Note: Award (M1) for their correct substitution into geometric sequence formula.
n=6 (A1)(ft) (C2)
Note: Follow through from part (a).
Award (A1)(A0) for u6=2 or u6 with or without working.
[2 marks]
S30=486(1−1330)1−13 (M1)
Note: Award (M1) for correct substitution into geometric series formula.
=729 (A1)(ft) (C2)
[2 marks]