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Date May 2008 Marks available 2 Reference code 08M.1.sl.TZ1.6
Level SL only Paper 1 Time zone TZ1
Command term Complete Question number 6 Adapted from N/A

Question

Consider the following logic propositions:

\(p:{\text{ Sean is at school}}\)

\(q:{\text{ Sean is playing a game on his computer}}{\text{.}}\)

Write in words, \(p \underline { \vee } q\).

[2]
a.

Write in words, the converse of \(p \Rightarrow \neg q\).

[2]
b.

Complete the following truth table for \(p \Rightarrow \neg q\).

[2]
c.

Markscheme

Either Sean is at school or Sean is playing a game on his computer but not both.     (A1)(A1)     (C2)

Note: (A1) for ‘either ... or but not both’ (A1) for correct statements. ‘Either’ can be omitted.

[2 marks]

a.

If Sean is not playing a game on his computer then Sean is at school.     (A1)(A1)     (C2)

Note: (A1) for ‘If ... then’ (A1) for correct propositions in the correct order.

[2 marks]

b.

     (A1)(A1)(ft)     (C2)

Note: (A1) for each correct column.

[2 marks]

c.

Examiners report

The common error in part (a) was not to include “but not both” and for (b), to give the inverse rather than the converse. The first column in the table (not \(q\)) was well done but a number of candidates answered the implication incorrectly.

a.

The common error in part (a) was not to include “but not both” and for (b), to give the inverse rather than the converse. The first column in the table (not \(q\)) was well done but a number of candidates answered the implication incorrectly.

b.

The common error in part (a) was not to include “but not both” and for (b), to give the inverse rather than the converse. The first column in the table (not \(q\)) was well done but a number of candidates answered the implication incorrectly.

c.

Syllabus sections

Topic 3 - Logic, sets and probability » 3.2 » Compound statements: implication, \( \Rightarrow \) ; equivalence, \( \Leftrightarrow \) ; negation, \(\neg \) ; conjunction, \( \wedge \) ; disjunction, \( \vee \) ; exclusive disjunction, \(\underline \vee \) .
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