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Date May 2007 Marks available 2 Reference code 07M.1.sl.TZ0.7
Level SL only Paper 1 Time zone TZ0
Command term Write down Question number 7 Adapted from N/A

Question

B and C are subsets of a universal set U such that

\(U = \left\{ {x:x \in \mathbb{Z},0 \leqslant x < 10} \right\},{\text{ }}B = \left\{ {{\text{prime numbers}} < 10} \right\},{\text{ }}C = \left\{ {x:x \in \mathbb{Z},1 < x \leqslant 6} \right\}.\)

List the members of sets

(i) \(B\)

(ii) \(C \cap B\)

(iii) \(B \cup C′\)

[4]
a.

Consider the propositions:

p : x is a prime number less than 10.

q : x is a positive integer between 1 and 7.

Write down, in words, the contrapositive of the statement, “If x is a prime number less than 10, then x is a positive integer between 1 and 7.”

[2]
b.

Markscheme

(i) \(B = 2, 3, 5, 7\)     (A1)

Brackets not required

(ii) \(C \cap B = 2, 3, 5\)     (A1)(ft)

Follow through only from incorrect B

(iii) \(C' = 0, 1, 7, 8, 9\)     (A1)(ft)

\(B \cup C' = 0, 1, 2, 3, 5, 7, 8, 9\)     (A1)(ft)

Note: Award (A1) for correct \(C'\) seen. The first (A1)(ft) in (iii) can be awarded only if C was listed incorrectly and a mark was lost as a result in (a)(ii). If C was not listed and \(C'\) is wrong, the first mark is lost. The second mark can (ft) within part (iii) as  well as from (i).     (C4)

 

[4 marks]

 

a.

“If x is not a positive integer between 1 and 7, then x is not a prime number less than 10.”     (A1)(A1)

Award (A1) for both (not) statements, (A1) for correct order.     (C2)

[2 marks]

b.

Examiners report

a) Many candidates included 1 as a prime number for set \(B\). Most candidates were able to list the intersection of \(B\) and \(C\) correctly with many receiving a follow through for their incorrect \(B\). Very few candidates were able to list \(B \cup C '\) correctly with many listing the intersection. It was disappointing that only a few candidates listed \(C'\) separately – those that did often received a mark for this working.

 

a.

b) The majority of candidates were able to write down the contrapositive correctly but many gave the inverse or the converse instead.

b.

Syllabus sections

Topic 3 - Logic, sets and probability » 3.2 » Compound statements: implication, \( \Rightarrow \) ; equivalence, \( \Leftrightarrow \) ; negation, \(\neg \) ; conjunction, \( \wedge \) ; disjunction, \( \vee \) ; exclusive disjunction, \(\underline \vee \) .
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