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Date November 2007 Marks available 2 Reference code 07N.1.sl.TZ0.3
Level SL only Paper 1 Time zone TZ0
Command term Calculate Question number 3 Adapted from N/A

Question

The fifth term of an arithmetic sequence is 20 and the twelfth term is 41.

(i) Find the common difference.

(ii) Find the first term of the sequence.

[3]
a.

Calculate the eighty-fourth term.

[1]
b.

Calculate the sum of the first 200 terms.

[2]
c.

Markscheme

(i) u5=u1+4d=20

u12=u1+11d=41     (M1)

(M1) for both equations correct (or (M1) for 20+7d=41)

7d=21

d=3     (A1)     (C2)

 

(ii) u1+12=20

u1=8     (A1)(ft)     (C1)

 

[3 marks]

a.

u84=8+(841)3

=257     (A1)(ft)     (C1)

[1 mark]

b.

S200=100(16+199×3)     (M1)

=61300     (A1)(ft)     (C2)

[2 marks]

c.

Examiners report

This question was generally answered well. Most of the candidates had a good understanding of how to use the formulae for an arithmetic sequence.

a.

This question was generally answered well. Most of the candidates had a good understanding of how to use the formulae for an arithmetic sequence.

b.

This question was generally answered well. Most of the candidates had a good understanding of how to use the formulae for an arithmetic sequence.

c.

Syllabus sections

Topic 1 - Number and algebra » 1.7 » Arithmetic sequences and series, and their applications.
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