| Date | May 2012 | Marks available | 2 | Reference code | 12M.1.sl.TZ2.10 |
| Level | SL only | Paper | 1 | Time zone | TZ2 |
| Command term | Find | Question number | 10 | Adapted from | N/A |
Question
The resting pulse rates of a group of 10 students who exercise regularly are given below.
65, 62, 75, 63, 69, 58, 65, 67, 55, 60
Find the median resting pulse rate of the students.
Find the mean resting pulse rate of the students.
A new student joins the class and the mean resting pulse rate of the group of 11 students becomes 65.
Find the resting pulse rate of the student who joined the group.
Markscheme
Attempt to order set of numbers (M1)
64 (A1) (C2)
[2 marks]
\(\frac{639}{10}\) (M1)
Note: Award (M1) for their sum divided by 10.
63.9 (A1) (C2)
[2 marks]
\(\frac{{(639 + x)}}{{11}} = 65\) or equivalent (M1)
\(x = 76\) (A1)(ft) (C2)
Notes: Award (M1) for setting up an equation (their part (b) \(\times 10 + x )/11 = 65\). Follow through from their sum seen in part (b). Accept correct alternative methods but not trial and error.
[2 marks]
Examiners report
This question proved to be relatively easy for most candidates. They could find the median, mean and also the pulse rate of the student who joined the group. Where mistakes were made, they were in not ordering the list of numbers. Part (c) presented the most challenge for weaker candidates.
This question proved to be relatively easy for most candidates. They could find the median, mean and also the pulse rate of the student who joined the group. Where mistakes were made, they were in not ordering the list of numbers. Part (c) presented the most challenge for weaker candidates.
This question proved to be relatively easy for most candidates. They could find the median, mean and also the pulse rate of the student who joined the group. Where mistakes were made, they were in not ordering the list of numbers. Part (c) presented the most challenge for weaker candidates.
