Date | May Specimen paper | Marks available | 1 | Reference code | SPM.1.SL.TZ0.10 |
Level | Standard Level | Paper | Paper 1 | Time zone | Time zone 0 |
Command term | Find | Question number | 10 | Adapted from | N/A |
Question
The following diagram shows part of the graph of f(x)=(6−3x)(4+x), x∈R. The shaded region R is bounded by the x-axis, y-axis and the graph of f.
Write down an integral for the area of region R.
Find the area of region R.
The three points A(0, 0) , B(3, 10) and C(a, 0) define the vertices of a triangle.
Find the value of a, the x-coordinate of C, such that the area of the triangle is equal to the area of region R.
Markscheme
A = ∫20(6−3x)(4+x)dx A1A1
Note: Award A1 for the limits x = 0, x = 2. Award A1 for an integral of f(x).
[2 marks]
28 A1
[1 mark]
28=0.5×a×10 M1
5.6(285) A1
[2 marks]
Examiners report
It was pleasing to see that, for those candidates who made a reasonable attempt at the paper, many were able to identify the correct values on the tree diagram.