Date | May 2022 | Marks available | 2 | Reference code | 22M.2.AHL.TZ1.6 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 1 |
Command term | Show that | Question number | 6 | Adapted from | N/A |
Question
Consider the function f(x)=2x-12x, x∈ℝ.
The function g is given by g(x)=x-1x2-2x-3, where x∈ℝ, x≠-1, x≠3.
Show that f is an odd function.
Solve the inequality f(x)≥g(x).
Markscheme
attempt to replace x with -x M1
f(-x)=2-x-12-x
EITHER
=12x-2x=-f(x) A1
OR
=-(2x-12x)(=-f(x)) A1
Note: Award M1A0 for a graphical approach including evidence that either the graph is invariant after rotation by 180° about the origin or the graph is invariant after a reflection in the y-axis and then in the x-axis (or vice versa).
so f is an odd function AG
[2 marks]
attempt to find at least one intersection point (M1)
x=-1.26686…, x=0.177935…, x=3.06167…
x=-1.27, x=0.178, x=3.06
-1.27≤x≤-1, A1
0.178≤x<3, A1
x≥3.06 A1
[4 marks]