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Date November 2019 Marks available 2 Reference code 19N.2.SL.TZ0.S_5
Level Standard Level Paper Paper 2 Time zone Time zone 0
Command term Find Question number S_5 Adapted from N/A

Question

The first two terms of a geometric sequence are  u 1 = 2.1 and  u 2 = 2.226 .

Find the value of r .

[2]
a.

Find the value of u 10 .

[2]
b.

Find the least value of n such that  S n > 5543 .

[3]
c.

Markscheme

valid approach        (M1)

eg        u 1 u 2 ,   2.226 2.1 ,   2.226 = 2.1 r

r = 1.06   (exact)       A1  N2

[2 marks]

a.

correct substitution        (A1)

eg        2.1 × 1.06 9

3.54790        A1  N2

u 10 = 3.55

[2 marks]

b.

correct substitution into  S n formula        (A1)

eg      2.1 ( 1.06 n 1 ) 1.06 1 ,   2.1 ( 1.06 n 1 ) 1.06 1 > 5543 ,   2.1 ( 1.06 n 1 ) = 332.58 ,  sketch of  S n and  y = 5543

correct inequality for n or crossover values       A1

eg        n > 87.0316 ,   S 87 = 5532.73   and   S 88 = 5866.79

n = 88        A1  N2

[3 marks]

c.

Examiners report

[N/A]
a.
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b.
[N/A]
c.

Syllabus sections

Topic 1—Number and algebra » SL 1.3—Geometric sequences and series
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Topic 1—Number and algebra

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