Date | November 2019 | Marks available | 2 | Reference code | 19N.2.AHL.TZ0.H_9 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 0 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
A body moves in a straight line such that its velocity, vms−1, after t seconds is given by v=2sin(t10+π5)csc(t30+π4) for 0⩽t⩽60.
The following diagram shows the graph of v against t. Point A is a local maximum and point B is a local minimum.
The body first comes to rest at time t=t1. Find
Determine the coordinates of point A and the coordinates of point B.
Hence, write down the maximum speed of the body.
the value of t1.
the distance travelled between t=0 and t=t1.
the acceleration when t=t1.
Find the distance travelled in the first 30 seconds.
Markscheme
A(7.47, 2.28) and B(43.4,−2.45) A1A1A1A1
[4 marks]
maximum speed is 2.45(ms−1) A1
[1 mark]
v=0⇒t1=25.1(s) (M1)A1
[2 marks]
∫t10vdt (M1)
=41.0(m) A1
[2 marks]
a=dvdt at t=t1=25.1 (M1)
a=−0.200(ms−2) A1
Note: Accept a=−0.2.
[2 marks]
attempt to integrate between 0 and 30 (M1)
Note: An unsupported answer of 38.6 can imply integrating from 0 to 30.
EITHER
∫300|v|dt (A1)
OR
41.0−∫30t1vdt (A1)
THEN
=43.3(m) A1
[3 marks]