Date | May 2019 | Marks available | 5 | Reference code | 19M.3.AHL.TZ0.Hca_5 |
Level | Additional Higher Level | Paper | Paper 3 | Time zone | Time zone 0 |
Command term | Prove and State | Question number | Hca_5 | Adapted from | N/A |
Question
Consider the differential equation , where .
Solve the differential equation and show that a general solution is where is a positive constant.
Prove that there are two horizontal tangents to the general solution curve and state their equations, in terms of .
Markscheme
* This question is from an exam for a previous syllabus, and may contain minor differences in marking or structure.
let M1
(A1)
(M1)
(A1)
Note: Or equivalent attempt at simplification.
A1
(M1)
(A1)
A1A1
Note: Award A1 for LHS and A1 for RHS and a constant.
M1
Note: Award M1 for substituting . May be seen at a later stage.
A1
Note: Award A1 for any correct equivalent equation without logarithms.
AG
[11 marks]
METHOD 1
(for horizontal tangents) M1
EITHER
using M1
A1
Note: Award M1A1 for .
OR
using implicit differentiation of
M1
Note: Accept differentiation of .
A1
THEN
tangents at A1A1
hence there are two tangents AG
METHOD 2
M1A1
this is a circle radius centre A1
hence there are two tangents AG
tangents at A1A1
[5 marks]