Date | May 2018 | Marks available | 2 | Reference code | 18M.2.AHL.TZ2.H_9 |
Level | Additional Higher Level | Paper | Paper 2 | Time zone | Time zone 2 |
Command term | Find | Question number | H_9 | Adapted from | N/A |
Question
The number of taxis arriving at Cardiff Central railway station can be modelled by a Poisson distribution. During busy periods of the day, taxis arrive at a mean rate of 5.3 taxis every 10 minutes. Let T represent a random 10 minute busy period.
Find the probability that exactly 4 taxis arrive during T.
Find the most likely number of taxis that would arrive during T.
Given that more than 5 taxis arrive during T, find the probability that exactly 7 taxis arrive during T.
During quiet periods of the day, taxis arrive at a mean rate of 1.3 taxis every 10 minutes.
Find the probability that during a period of 15 minutes, of which the first 10 minutes is busy and the next 5 minutes is quiet, that exactly 2 taxis arrive.
Markscheme
(M1)
= 0.164 A1
[2 marks]
METHOD 1
listing probabilities (table or graph) M1
mode X = 5 (with probability 0.174) A1
Note: Award M0A0 for 5 (taxis) or mode = 5 with no justification.
METHOD 2
mode is the integer part of mean R1
E(X) = 5.3 ⇒ mode = 5 A1
Note: Do not allow R0A1.
[2 marks]
attempt at conditional probability (M1)
or equivalent A1
= 0.267 A1
[3 marks]
METHOD 1
the possible arrivals are (2,0), (1,1), (0,2) (A1)
A1
attempt to compute, using sum and product rule, (M1)
0.070106… × 0.52204… + 0.026455… × 0.33932… + 0.0049916… × 0.11028… (A1)(A1)
Note: Award A1 for one correct product and A1 for two other correct products.
= 0.0461 A1
[6 marks]
METHOD 2
recognising a sum of 2 independent Poisson variables eg Z = X + Y R1
P(Z = 2) = 0.0461 (M1)A3
[6 marks]