Date | May Example questions | Marks available | 5 | Reference code | EXM.1.SL.TZ0.2 |
Level | Standard Level | Paper | Paper 1 (without calculator) | Time zone | Time zone 0 |
Command term | Show that and Hence | Question number | 2 | Adapted from | N/A |
Question
A set of data comprises of five numbers x1,x2,x3,x4,x5x1,x2,x3,x4,x5 which have been placed in ascending order.
Recalling definitions, such as the Lower Quartile is the n+14thn+14th piece of data with the data placed in order, find an expression for the Interquartile Range.
Hence, show that a data set with only 5 numbers in it cannot have any outliers.
Give an example of a set of data with 7 numbers in it that does have an outlier, justify this fact by stating the Interquartile Range.
Markscheme
LQ=x1+x22,UQ=x4+x52,IQR=x4+x5−x1−x22LQ=x1+x22,UQ=x4+x52,IQR=x4+x5−x1−x22 M1A1
[2 marks]
UQ+1.5IQR=1.25x4+1.25x5−0.75x1−0.75x2⩾x5 M1A1
Since 1.25x4+0.25x5⩾0.75x1+0.75x2 due to the ascending order. R1
Similarly LQ−1.5IQR=1.25x1+1.25x2−0.75x4−0.75x5⩽x1 M1A1
Since 0.25x1+1.25x2⩽0.75x3+0.75x4 due to the ascending order.
So there are no outliers for a data set of 5 numbers. AG
[5 marks]
For example 1, 2, 3, 4, 5, 6, 100 where IQR=4 A1A1
[2 marks]