Date | November 2021 | Marks available | 1 | Reference code | 21N.2.HL.TZ0.5 |
Level | Higher level | Paper | Paper 2 | Time zone | 0 - no time zone |
Command term | Show that | Question number | 5 | Adapted from | N/A |
Question
A square loop of side 5.0 cm enters a region of uniform magnetic field at t = 0. The loop exits the region of magnetic field at t = 3.5 s. The magnetic field strength is 0.94 T and is directed into the plane of the paper. The magnetic field extends over a length 65 cm. The speed of the loop is constant.
Show that the speed of the loop is 20 cm s−1.
Sketch, on the axes, a graph to show the variation with time of the magnetic flux linkage in the loop.
Sketch, on the axes, a graph to show the variation with time of the magnitude of the emf induced in the loop.
There are 85 turns of wire in the loop. Calculate the maximum induced emf in the loop.
The resistance of the loop is 2.4 Ω. Calculate the magnitude of the magnetic force on the loop as it enters the region of magnetic field.
Show that the energy dissipated in the loop from t = 0 to t = 3.5 s is 0.13 J.
The mass of the wire is 18 g. The specific heat capacity of copper is 385 J kg−1 K−1. Estimate the increase in temperature of the wire.
Markscheme
✓
shape as above ✓
shape as above ✓
Vertical lines not necessary to score.
Allow ECF from (b)(i).
ALTERNATIVE 1
maximum flux at «» «Wb» ✓
emf = «» «V» ✓
ALTERNATIVE 2
emf induced in one turn = BvL = «V» ✓
emf «V» ✓
Award [2] marks for a bald correct answer.
Allow ECF from MP1.
OR «A» ✓
«N» ✓
Allow ECF from (c)(i).
Award [2] marks for a bald correct answer.
Energy is being dissipated for 0.50 s ✓
« J»
OR
« J» ✓
Allow ECF from (b) and (c).
Watch for candidates who do not justify somehow the use of 0.5 s and just divide by 2 their answer.
✓
«K» ✓
Allow [2] marks for a bald correct answer.
Award [1] for a POT error in MP1.